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Calculate the final concentration of NaOH when 42.0 mL of 0.130 M NaOH is mixed with 37.6 mL of 0.360 M NaOH. Assume that the volumes are additive.

Answer :

Mixed molarity is 0.254 M

The volumes are additive is 1.22 M

Part A

mixed molarity = (M1 V1 + M2V2 )/ V1+V2

= (0.150 x 42 + 0.370 x 37.6 ) / (42+37.6)

= 0.254 M

NaOH = 0.254M

[Na+ ]= 0.254M

[OH-]= 0.254M

Part B

[Na+] = 2 x 44 x 0.1 / 44 + 25

= 0.1275 M

{SO4-2] = 44 x 0.1 / 44 + 25 = 0.063 M

[K+] =25 x 0.17 / 44 + 25 = 0.062 M

[Cl-] = 25 x 0.17 / 44 + 25 = 0.062 M

Part C

KCl moles = 3.70 / 74.55 = 0.0493

KCl molarity = 0.0493 / 0.075 = 0.66M

[K+] = 0.66 M

[Ca+2] = 0.280 M

[Cl-] = 0.66 + 2 x 0.280 = 1.22 M

Volume is a measurement of three-dimensional space that is occupied. Numerous imperial units or SI-derived units, such as the cubic meter and liter, are frequently used to quantify it numerically (such as the gallon, quart, and cubic inch). Volume and length (cubed) have a symbiotic relationship. The volume of a container is typically thought of as its capacity, not as the amount of space it takes up. In other words, the volume is the amount of fluid (liquid or gas) that the container may hold.

Volume was initially measured using naturally occurring vessels of a comparable shape and then with standardized containers. Arithmetic formulas can be used to quickly calculate the volume of several straightforward three-dimensional shapes.

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Rewritten by : Barada

Final answer:

The total molarity of the solutions when 42.0 ml of 0.130 M NaOH is mixed with 37.6 ml of 0.360 M NaOH is 0.2386 M.

Explanation:

To solve this problem we would need to find the total moles of NaOH and the total volume in the solution. The molarity (M) is defined as moles of solute per liter of solution. So, we can find the moles for each solution by multiplying the volume (in L) and the molarity and then add the volumes and moles together.

For the first solution, the total moles of NaOH is (0.042 L)(0.130 M) = 0.00546 mol. For the second solution, the total moles of NaOH is (0.0376 L)(0.360 M) = 0.013536 mol. The total moles of NaOH in the two solutions would be 0.00546 mol + 0.013536 mol = 0.018996 mol.

Similarly, the total volume of the solution would be 42.0 ml + 37.6 ml = 79.6 ml. Convert this to L and you get 0.0796 L. Using the formula of molarity which is M = moles/L, we will have M = 0.018996 mol / 0.0796 L = 0.2386 M. Thus, the molarity of the combined solutions of NaOH is 0.2386M.

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