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A chemist must dilute 62.6 mL of 1.37 M aqueous sodium carbonate (Na₂CO₃) solution until the concentration falls to 1.00 M. He will do this by adding distilled water to the solution until it reaches a certain final volume.

Calculate this final volume, in milliliters. Round your answer to 3 significant digits.

Answer :

Rounding to three significant digits, the final volume of the solution would be 85.5 mL.

To dilute the 62.6 mL of 1.37 M sodium carbonate (Na₂CO₃) solution to a concentration of 1.00 M, you will need to add distilled water. The final volume of the solution can be calculated using the equation:

M₁V₁ = M₂V₂

Where:
M₁ is the initial concentration of the solution (1.37 M)
V₁ is the initial volume of the solution (62.6 mL)
M₂ is the final concentration of the solution (1.00 M)
V₂ is the final volume of the solution (which we need to find)

To solve for V₂, we can rearrange the equation:

V₂ = (M₁V₁) / M₂

Plugging in the values, we have:

V₂ = (1.37 M * 62.6 mL) / 1.00 M

Calculating this, we get:

V₂ = 85.462 mL

Rounding to three significant digits, the final volume of the solution would be 85.5 mL.

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