High School

We appreciate your visit to The enthalpy and entropy of vaporization of a substance are 38 6 kJ mol and 109 J mol K respectively What is the boiling point. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

The enthalpy and entropy of vaporization of a substance are 38.6 kJ/mol and 109 J/mol K, respectively. What is the boiling point of the substance in °C?

Answer :

Final answer:

The boiling point of the substance is equal to the initial temperature (T1).

Explanation:

To find the boiling point of the substance, we can use the Clausius-Clapeyron equation:

ln(P2/P1) = (ΔHvap/R) * (1/T1 - 1/T2)

Where:

  • P1 and P2 are the initial and final pressures, respectively.
  • ΔHvap is the enthalpy of vaporization.
  • R is the ideal gas constant (8.314 J/mol K).
  • T1 and T2 are the initial and final temperatures, respectively.

In this case, we are given the enthalpy of vaporization (ΔHvap = 38.6 kJ/mol) and the entropy of vaporization (ΔSvap = 109 J/mol K). We need to find the boiling point in °C, which corresponds to the final temperature (T2).

Since we are given the values in kJ/mol and J/mol K, we need to convert them to J/mol and J/mol °C, respectively, to match the units of the ideal gas constant (R).

ΔHvap = 38.6 kJ/mol = 38,600 J/mol

ΔSvap = 109 J/mol K

Now, we can rearrange the Clausius-Clapeyron equation to solve for T2:

ln(P2/P1) = (ΔHvap/R) * (1/T1 - 1/T2)

Since we are given the initial pressure (P1) and the atmospheric pressure is usually 1 atm, we can assume P2 = 1 atm.

ln(1/1) = (38,600 J/mol / (8.314 J/mol K)) * (1/T1 - 1/T2)

0 = (38,600 / 8.314) * (1/T1 - 1/T2)

0 = 4649.94 * (1/T1 - 1/T2)

1/T1 - 1/T2 = 0

1/T1 = 1/T2

T1 = T2

Therefore, the boiling point of the substance is equal to the initial temperature (T1).

Learn more about entropy here:

https://brainly.com/question/32167470

#SPJ11

Thanks for taking the time to read The enthalpy and entropy of vaporization of a substance are 38 6 kJ mol and 109 J mol K respectively What is the boiling point. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada