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Two objects are pulled across a frictionless surface. Determine the acceleration of the objects for [tex]m_1 = 6.00 \, \text{kg}[/tex], [tex]m_2 = 4.00 \, \text{kg}[/tex], and [tex]F = 8.00 \, \text{N}[/tex].

1) [tex]1.50 \, \text{m/s}^2[/tex]
2) [tex]4.00 \, \text{m/s}^2[/tex]
3) [tex]0.80 \, \text{m/s}^2[/tex]
4) [tex]0.75 \, \text{m/s}^2[/tex]

Answer :

Final answer:

The acceleration of the two objects being pulled across a frictionless surface with given masses of 6.00 kg and 4.00 kg with a force of 8.00 N is 3) 0.80 m/s².

Explanation:

To determine the acceleration of two objects being pulled across a frictionless surface, we can use Newton's second law of motion, which states that the acceleration of an object is the net force acting upon it divided by its mass (F = ma). The total force in this scenario is the force f pulling the objects, and the total mass is the sum of the masses of the two objects (m1 + m2).

The formula to find acceleration (a) is:

a = f / (m1 + m2

Substituting the given values:

a = 8.00 N / (6.00 kg + 4.00 kg)

a = 8.00 N / 10.00 kg

a = 0.80 m/s²

Therefore, the acceleration of the objects is 0.80 m/s².

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