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A woman is pushing a box along the ground. She is exerting a force of 156 N on the box. The box has a mass of 84 kg. If the coefficient of kinetic friction between the box and the ground is 0.16, what is the acceleration of the box?

Answer :

The coefficient of kinetic friction between the box and the ground is then the acceleration of the box is approximately 0.29 m/s².

The acceleration of the box can be determined by applying Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

In this case, the woman is exerting a force of 156 N on the box.

The box has a mass of 84 kg.

To find the net force acting on the box, we need to subtract the force of kinetic friction from the applied force.

The force of kinetic friction can be calculated by multiplying the coefficient of kinetic friction (0.16) by the normal force.

The normal force is equal to the weight of the box, which can be calculated by multiplying the mass (84 kg) by the acceleration due to gravity (9.8 m/s²).

So, the normal force is 823.2 N (84 kg × 9.8 m/s²).

Now, we can calculate the force of kinetic friction by multiplying the coefficient of kinetic friction (0.16) by the normal force (823.2 N)0.

The force of kinetic friction is 131.712 N (0.16 × 823.2 N).

To find the net force, we subtract the force of kinetic friction from the applied force:

156 N - 131.712 N = 24.288 N.

Now, we can calculate the acceleration using Newton's second law of motion.

The net force is 24.288 N, and the mass is 84 kg.

The formula is:

acceleration = net force / mass

acceleration = 24.288 N / 84 kg

acceleration ≈ 0.29 m/s².

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