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Answer :
To determine if the large counts condition for this problem is met, we first need to calculate the combined sample proportion. This is an important step as it helps in conducting hypothesis tests for comparing two proportions.
Here’s how you can calculate the combined sample proportion, [tex]\(\hat{p}_c\)[/tex], using the given data:
1. Identify the Sample Sizes and Counts:
- The total number of adults who exercise regularly, [tex]\( n_1 = 50 \)[/tex].
- The number of adults who exercise and got sick, [tex]\( x_1 = 18 \)[/tex].
- The total number of adults who do not exercise regularly, [tex]\( n_2 = 75 \)[/tex].
- The number of adults who do not exercise and got sick, [tex]\( x_2 = 56 \)[/tex].
2. Calculate the Combined Proportion:
- First, sum the number of "successes" (individuals who got sick) from both groups: [tex]\( x_1 + x_2 = 18 + 56 = 74 \)[/tex].
- Then, sum the total number of individuals from both groups: [tex]\( n_1 + n_2 = 50 + 75 = 125 \)[/tex].
- Finally, use the formula for the combined sample proportion:
[tex]\[
\hat{p}_c = \frac{x_1 + x_2}{n_1 + n_2} = \frac{74}{125}
\][/tex]
3. Compute [tex]\(\hat{p}_c\)[/tex]:
Divide 74 by 125 to get [tex]\(\hat{p}_c\)[/tex]. This calculation results in:
[tex]\[
\hat{p}_c \approx 0.592
\][/tex]
Thus, the combined sample proportion, [tex]\(\hat{p}_c\)[/tex], is 0.592. This value will help determine if the large counts condition for performing a hypothesis test is satisfied, ensuring the sample proportion estimates are approximately normally distributed.
Here’s how you can calculate the combined sample proportion, [tex]\(\hat{p}_c\)[/tex], using the given data:
1. Identify the Sample Sizes and Counts:
- The total number of adults who exercise regularly, [tex]\( n_1 = 50 \)[/tex].
- The number of adults who exercise and got sick, [tex]\( x_1 = 18 \)[/tex].
- The total number of adults who do not exercise regularly, [tex]\( n_2 = 75 \)[/tex].
- The number of adults who do not exercise and got sick, [tex]\( x_2 = 56 \)[/tex].
2. Calculate the Combined Proportion:
- First, sum the number of "successes" (individuals who got sick) from both groups: [tex]\( x_1 + x_2 = 18 + 56 = 74 \)[/tex].
- Then, sum the total number of individuals from both groups: [tex]\( n_1 + n_2 = 50 + 75 = 125 \)[/tex].
- Finally, use the formula for the combined sample proportion:
[tex]\[
\hat{p}_c = \frac{x_1 + x_2}{n_1 + n_2} = \frac{74}{125}
\][/tex]
3. Compute [tex]\(\hat{p}_c\)[/tex]:
Divide 74 by 125 to get [tex]\(\hat{p}_c\)[/tex]. This calculation results in:
[tex]\[
\hat{p}_c \approx 0.592
\][/tex]
Thus, the combined sample proportion, [tex]\(\hat{p}_c\)[/tex], is 0.592. This value will help determine if the large counts condition for performing a hypothesis test is satisfied, ensuring the sample proportion estimates are approximately normally distributed.
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