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Answer :
The molality of the MgBr₂ solution is approximately 3.63 mol/kg or 3.63 m.
The freezing point of an aqueous solution of MoBr can be calculated using the equation ΔT = Kf * m, where ΔT is the change in freezing point, Kf is the cryoscopic constant for the solvent (water), and m is the molality of the solution (moles of solute per kg of solvent).
Given the freezing point depression of 1.86°C for MgBr₂ in water, we can set up the equation as 1.86°C = Kf * m. Substituting the given values, we have 1.86°C = 0.512°C/m * m, which simplifies to m = 1.86°C / 0.512°C/m.
Therefore, the molality of the MgBr₂ solution is approximately 3.63 mol/kg or 3.63 m.
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