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At the instant that a cake is removed from the oven, its temperature is 350 degrees F. After 10 minutes, the cake's temperature is 200 degrees F. If the room temperature is 70 degrees F, how much longer will it take for the cake to cool to 90 degrees F?

Answer :

It will take an additional 7.33 minutes for the cake to cool from 200 degrees F to 90 degrees F after the initial 10 minutes of cooling.

To calculate how much longer it will take for the cake to cool to 90 degrees F, we need to first determine the rate at which the cake is cooling. We can do this by calculating the temperature difference between the cake and the room and dividing it by the time it takes for that temperature difference to occur.
In this case, the temperature difference between the cake and the room is 280 degrees F (350-70=280) when the cake is removed from the oven. After 10 minutes, the temperature difference is 130 degrees F (200-70=130). Therefore, the cake is cooling at a rate of 15 degrees F per minute (280-130=150 degrees F in 10 minutes; 150/10=15).
To determine how much longer it will take for the cake to cool to 90 degrees F, we need to calculate the time it takes for the temperature to drop from 200 degrees F to 90 degrees F. This is a temperature difference of 110 degrees F (200-90=110), so it will take approximately 7.33 minutes (110/15=7.33) for the cake to cool from 200 degrees F to 90 degrees F.

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