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Answer :
Final answer:
The capacitors connected in series in a circuit have a total capacitance of approximately 2.31 µF. This is calculated using the inverse of the sum of the inverses of each individual capacitance.
Explanation:
In Physics, when capacitors are connected in series, the total capacitance (C) can be calculated using the inverse of the sum of the inverses of each individual capacitance value. It is similar to resistors in parallel connection. The equation is 1/C = 1/C1 + 1/C2 + 1/C3. Where C1, C2, C3 are the capacitance values of the capacitors. For the given values: C1 = 4.5 µF, C2 = 12 µF, C3 = 6 µF. Substituting these values, we get 1/C = 1/4.5 + 1/12 + 1/6. Solving this yields a total capacitance C of approximately 2.31 µF for the circuit connected to the battery.
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