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Answer :
Final answer:
The energy required to remove both electrons from a neutral helium atom is 79 eV.
Explanation:
The energy required to remove both electrons from a neutral helium atom can be calculated based on the ionization energies of helium. The first ionization energy, which is the energy required to remove one electron, is experimentally measured to be 24.6 eV. The second ionization energy, which is the energy required to remove the second electron, can be calculated as the difference between the energy of a helium ion (He+) and the energy of a neutral helium atom. The energy of a helium ion is -54.4 eV. Therefore, the energy required to remove both electrons is:
24.6 eV + 54.4 eV = 79 eV
Hence, the correct answer is Option A: 79
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