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Answer :
The F2 effuses 1.87 times faster than Cl2. This is because the rate of effusion is inversely proportional to the square root of the molar mass of the gas. Since F2 has a lower molar mass than Cl2, it will effuse faster. ,the ratio of the effusion rates is equal to the square root of the molar mass of Cl2 divided by the molar mass of F2, which is approximately 1.87
The ratio of effusion for F2 gas to Cl2 gas can be determined using Graham's Law of Effusion:
Rate₁/Rate₂ = √(M₂/M₁)
Here, Rate₁ and Rate₂ are the effusion rates of F2 and Cl2, respectively, and M₁ and M₂ are their molar masses.
1. The molar mass of F2 is 38 g/mol (19 g/mol for each F atom).
2. The molar mass of Cl2 is 71 g/mol (35.5 g/mol for each Cl atom).
Now, plug in the values into Graham's Law equation:
Rate(F2)/Rate(Cl2) = √(71/38)
Rate(F2)/Rate(Cl2) ≈ 1.37
So, F2 effuses 1.37 times faster than Cl2. The correct answer is B) F2 effuses 1.37 times faster.
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