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Answer :
Final answer:
The ball thrown with a speed of 29.4 m/s and at an angle of 35.5 degrees goes 14.72 meters above the cliff.
Explanation:
In order to determine the maximum height of the ball above the cliff, we first need to find out the ball's vertical velocity. We do this by multiplying the initial speed (29.4 m/s) by the sine of the angle of projection (35.5 degrees). Once we have the vertical velocity, we need to find the time at which the ball reaches its maximum height. This is calculated by dividing the vertical velocity by the acceleration due to gravity (9.81 m/s²). Finally, the maximum height is achieved by taking half the product of the time and the vertical velocity. So:
Vertical Velocity = 29.4 m/s * sin(35.5) = 16.99 m/s
Time = 16.99 m/s / 9.81 m/s² = 1.73 s
Max Height = 0.5 * 1.73 s * 16.99 m/s = 14.72 m
Thus, the ball goes 14.72 meters above the cliff.
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