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An Otto cycle operates between maximum and minimum pressures of 600 kPa and 100 kPa. The minimum and maximum temperatures in the cycle are 27ºC and 1600 K. Determine the thermal efficiency of the cycle.

Answer :

Final answer:

The thermal efficiency of the Otto cycle with temperatures of 27°C and 1600K is approximately 61%

Explanation:

The efficiency (η) of an Otto cycle, a cycle that describes a certain type of internal combustion engine, is given by the formula η = 1 - (1/r^(γ-1)), where r is the compression ratio and γ is the heat capacity ratio. Here we have to use temperatures instead.

η = 1 - (Tmin/Tmax)^(γ-1), where Tmin is the minimum temperature, Tmax is the maximum temperature, and γ is the heat capacity ratio (assumed to be 1.4 for standard air).

First, convert the minimum temperature to Kelvin: Tmin = 27°C + 273 = 300K. Then, plug the temperatures into the equation: η = 1 - (300 K / 1600 K)^(1.4-1) ≈ 0.61 or 61%.

So, the thermal efficiency of the Otto cycle given the provided temperatures is approximately 61% under the assumption of ideal air as the working fluid.

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