High School

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If [tex]f(4) = 246.4[/tex] when [tex]r = 0.04[/tex] for the function [tex]f(t) = P e^{rt}[/tex], then what is the approximate value of [tex]P[/tex]?

A. 50
B. 289
C. 210
D. 1220

Answer :

Let's solve the problem step-by-step:

We have the function [tex]\( f(t) = P e^{r \cdot t} \)[/tex], and we're given that when [tex]\( t = 4 \)[/tex], [tex]\( f(4) = 246.4 \)[/tex] and [tex]\( r = 0.04 \)[/tex]. We need to find the approximate value of [tex]\( P \)[/tex].

Here's how we can find [tex]\( P \)[/tex]:

1. Substitute the known values into the function:

[tex]\[
f(4) = P \cdot e^{0.04 \times 4}
\][/tex]

[tex]\[
246.4 = P \cdot e^{0.16}
\][/tex]

2. Solve for [tex]\( P \)[/tex]:

We need to calculate [tex]\( e^{0.16} \)[/tex]. This is an exponential function where [tex]\( e \approx 2.71828 \)[/tex]. When calculated, [tex]\( e^{0.16} \approx 1.17351 \)[/tex].

3. Divide [tex]\( f(4) \)[/tex] by [tex]\( e^{0.16} \)[/tex] to find [tex]\( P \)[/tex]:

[tex]\[
P = \frac{246.4}{1.17351} \approx 209.97
\][/tex]

4. Approximate [tex]\( P \)[/tex]:

The approximate value of [tex]\( P \)[/tex] is [tex]\( 210 \)[/tex].

Therefore, the correct option that closely matches this value is C. 210.

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