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Answer :
To solve this problem, we need to understand the relationship between voltage, energy, and charge.
In physics, the relationship is given by the formula:
[tex]E = V \times Q[/tex]
where:
- [tex]E[/tex] is the energy transferred in joules (J),
- [tex]V[/tex] is the voltage in volts (V),
- [tex]Q[/tex] is the charge in coulombs (C).
We are given:
- Voltage [tex]V = 13[/tex] V,
- Energy transferred [tex]E = 6 \times 10^4[/tex] J.
We need to find the charge [tex]Q[/tex]. We can rearrange the formula to solve for [tex]Q[/tex]:
[tex]Q = \frac{E}{V}[/tex]
Substitute the given values into the formula:
[tex]Q = \frac{6 \times 10^4}{13}[/tex]
Calculating this, we have:
[tex]Q \approx 4615.384615[/tex]
Rounded to 0 decimal places, the charge [tex]Q[/tex] is approximately 4615 C.
Therefore, the amount of charge that flows through the wire is 4615 coulombs.
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Rewritten by : Barada
