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The slopes of the lines are:
WX = 2
XY = -1.5
YZ = 4
WZ = -1
Given is a polygon on a coordinate plane with vertices =
W = (-5, 1)
X = (-3, 5)
Y = (-1, 2)
Z = (-2, -2)
We need to find the slopes of line =
WX, XY, YZ and WZ
To find the slopes of the lines connecting the vertices of the polygon, we can use the formula for the slope between two points (x₁, y₁) and (x₂, y₂):
slope = (y₂ - y₁) / (x₂ - x₁)
Let's calculate the slopes for each line:
1) Slope of line WX:
W = (-5, 1)
X = (-3, 5)
slope(WX) = (5 - 1) / (-3 - (-5))
= 4 / 2
= 2
So, the slope of line WX is 2.
2) Slope of line XY:
X = (-3, 5)
Y = (-1, 2)
slope(XY) = (2 - 5) / (-1 - (-3))
= -3 / 2
= -1.5
So, the slope of line XY is -1.5.
3) Slope of line YZ:
Y = (-1, 2)
Z = (-2, -2)
slope(YZ) = (-2 - 2) / (-2 - (-1))
= -4 / (-1)
= 4
So, the slope of line YZ is 4.
4) Slope of line WZ:
W = (-5, 1)
Z = (-2, -2)
slope(WZ) = (-2 - 1) / (-2 - (-5))
= -3 / 3
= -1
So, the slope of line WZ is -1.
Therefore, the slopes of the lines are:
WX = 2
XY = -1.5
YZ = 4
WZ = -1
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Rewritten by : Barada
Answer/Step-by-step explanation:
WX: 4.47
[tex]4^{2} + 2^{2} = 20\\\sqrt{20} = 4.47[/tex]
XY: 3.61
[tex]3^{2} + 2^{2} = 13\\\sqrt{13} = 3.61[/tex]
YZ: 4.12
[tex]1^{2} + 4^{2} = 17\\\sqrt{17} =4.12[/tex]
WZ: 4.24
[tex]3^{2} + 3^{2} = 18 \\\sqrt{18} = 4.24[/tex]
