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A dog food company makes dog food out of chicken and grain. Each bag of dog food must contain at least 200 grams of protein and at least 150 grams of fat. Chicken has 10 grams of protein and 5 grams of fat per ounce. Grain has 2 grams of protein and 2 grams of fat per ounce. Each bag of dog food must also include at least 5 ounces of chicken and at least 15 ounces of grain. If chicken costs $0.10 per ounce and grain costs $0.01 per ounce, how many ounces of each should the company use in each bag of dog food in order to keep cost as low as possible?

Set up this linear programming problem. Let [tex]x[/tex] be the number of ounces of chicken and let [tex]y[/tex] be the number of ounces of grain.

The objective function is:

A. Maximize [tex]C = 5x + 15y[/tex]
B. Maximize [tex]C = 0.1x + 0.01y[/tex]
C. Minimize [tex]C = 5x + 15y[/tex]
D. Minimize [tex]C = 0.1x + 0.01y[/tex]
E. Minimize [tex]C = 5x + 2y[/tex]

Answer :

The objective function is option D. Minimize C = 0.1x + 0.01y.

The objective function is the equation that represents the quantity that needs to be optimized or minimized. In this case, the company wants to keep the cost as low as possible. The cost is determined by the amount of chicken and grain used in each bag of dog food. Therefore, the objective function is the cost equation.

The cost of chicken is $0.10 per ounce and the cost of grain is $0.01 per ounce. Thus, the cost equation is:

C = 0.10x + 0.01y

where C is the total cost of the dog food in dollars, x is the number of ounces of chicken, and y is the number of ounces of grain.

Therefore, the correct answer is option D. Minimize C = 0.1x + 0.01y.

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