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Answer :
Final answer:
Susie can have a minimum of 18 pennies to satisfy the given conditions of having 2 left over when divided by 4 and 3 left over when divided by 5.
Explanation:
This student's question involves finding the smallest number of pennies that Susie can have based on two given conditions involving divisibility and remainders. This is a classic problem that can be solved using the Chinese remainder theorem or by systematic trial and error.
To find the least number of pennies (least common number) that satisfy both conditions, we would list multiples of 4 and add 2 (to account for the remainder), and list multiples of 5 and add 3, then find the smallest number that appears in both lists. The solution gives us the least number of pennies that works for both conditions.
By trying the smallest multiples, we get 4x+2=6,10,14,18,… and 5y+3=8,13,18,… Hence, the least amount of pennies Susie can have that satisfies both conditions is 18.
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Answer:
The least ammount of pennies would be 18 I belive.
Step-by-step explanation: