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Bob builds trailers to tow cars. He was hired to build a trailer that has an area of 96 square feet. The length of the trailer is 4 feet less than twice the width. What are the width and length of the trailer?

Answer :

Based on the given information, the width of the trailer is 8 feet, and the length is 12 feet.

How to find width and length

Let's denote the width of the trailer as w (in feet).

According to the given information, the length of the trailer is 4 feet less than twice the width. We can express this as:

Length = 2w - 4

To find the area of the trailer, use the formula for the area of a rectangle: Area = Length * Width.

Substituting the values, we have:

96 = (2w - 4) * w

Expanding and rearranging the equation

2w^2 - 4w - 96 = 0

To solve this quadratic equation, factor it or use the quadratic formula. Let's use the quadratic formula:

w = (-b ± √([tex]b^2[/tex] - 4ac)) / (2a)

In this case, a = 2, b = -4, and c = -96.

Plugging in these values, we have:

w = (-(-4) ± √[tex]((-4)^2[/tex] - 4 * 2 * (-96))) / (2 * 2)

w = (4 ± √(16 + 768)) / 4

w = (4 ± √784) / 4

w = (4 ± 28) / 4

Now we have two possible solutions for the width:

w = (4 + 28) / 4 = 32 / 4 = 8 feet

w = (4 - 28) / 4 = -24 / 4 = -6 feet

Since width cannot be negative in this context, we discard the negative solution.

Therefore, the width of the trailer is 8 feet.

To find the length, substitute the width value into the expression we derived earlier:

Length = 2w - 4 = 2 * 8 - 4 = 16 - 4 = 12 feet

Therefore, the width of the trailer is 8 feet, and the length is 12 feet.

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