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A golfer rides in a golf cart at an average speed of 3.59 m/s for 39.3 seconds. She then gets out of the cart and starts walking at an average speed of 1.46 m/s.

For how long (in seconds) must she walk if her average speed for the entire trip, riding and walking, is 1.72 m/s?

Answer :

The golfer does not need to walk for any particular time to maintain an average speed of 1.72 m/s for the entire trip.

To solve this problem, we can use the concept of average speed, which is calculated by dividing the total distance traveled by the total time taken.

Let's start by finding the total distance traveled while riding in the golf cart. We can use the formula:

Distance = Speed × Time

Distance = 3.59 m/s × 39.3 s

Distance = 141.387 m (rounded to three decimal places)

Now, let's assume the golfer walks for time t (in seconds). We can calculate the total distance covered while walking:

Distance = Speed × Time

Distance = 1.46 m/s × t

To maintain an average speed of 1.72 m/s for the entire trip, the total distance traveled while walking and riding should be equal to the distance covered while riding the cart:

141.387 m + 1.46 m/s × t = 141.387 m

Let's solve for t:

1.46 m/s × t = 0

Since the left side of the equation is zero, it means t can be any value. The golfer does not need to walk to maintain the average speed of 1.72 m/s. Therefore, she does not need to walk for any specific duration.

Therefore, the golfer must walk for 1.72 m/s

To learn more about speed click here; brainly.com/question/31035613

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