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What is the wavelength of the Lyman series transition that starts at [tex]n=4[/tex]?

A. 9.73 x 10^-8 nm
B. 91.2 nm
C. 97.3 nm
D. 102.7 nm

Answer :

Final answer:

The wavelength of a transition in the Lyman series of hydrogen that starts at n=4 is 97.3nm, which is option c.

Explanation:

The question is asking for the wavelength of a transition in the Lyman series of hydrogen that starts at n=4. The Lyman series of spectral lines of the hydrogen atom are those for which the photon energy results from the transition of an electron from a higher energy level (n > 1) to the lowest energy level (n = 1). According to the Rydberg formula for hydrogen, we can define the frequency of light that will be emitted during this transition:

1/λ = RZ² *( 1/n1² - 1/n2²).

In the case of the Lyman series, which is a series of lines in the ultraviolet region, n1 = 1 and n2 >= 2. For a transition that starts at n=4, therefore, the calculation becomes:

1/λ = RZ² *(1/1² - 1/4²).

Upon solving this equation with the known constant values, we find that the wavelength (λ) is 97.3 nm, which corresponds to option c.

Learn more about Lyman series here:

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