Answer :

Final answer:

To find the volume of the initial solution required to make a less concentrated solution, use the formula M1V1 = M2V2. In this case, you would need 99.6 mL of the 6.55 M HCl solution to make 450 mL of 1.45 M HCl solution.

Explanation:

The subject of this question is the concept of molarity and dilution in chemistry. Molarity is defined as the concentration of a solution expressed as the number of moles of solute per liter of solution. In this case, to make a smaller concentration from a solution of higher concentration, a process called dilution is applied.

In this particular example, using the formula M1V1 = M2V2, where M1 is the initial molarity (6.55 M), V1 is the volume of the initial solution we're finding, M2 is the final molarity (1.45 M), and V2 is the final volume (450 ml or 0.45 L), we get: 6.55M * V1 = 1.45M * 0.45 L. Solving for V1 gives 0.0996 L or 99.6 ml, which corresponds to answer B. So, 99.6 mL of the initial 6.55 M HCl solution is required to prepare 450 mL of 1.45 M HCl solution.

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