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Particles q1 = -53.0 mc, 92 = -105 mc, and 93 = 88.0 mc are in a line. Particles q1 and 92 are separated by 0.50 m and particles 92 and 93 are separated by 0.95 m. What is the net force on particle 93?

Answer :

Final answer:

Using Coulomb's Law and the given parameters, the net force on particle 93 is calculated by summing up the electrostatic forces due to particles q1 and q2 on q3. Take into account the distances between particles.

Explanation:

To determine the net force on particle 93, we have to find the forces particle 93 experiences due to the other particles and sum those up.

Using Coulomb's Law, the electrostatic force between two particles is F = k * |q1 * q2| / r^2, where k is Coulomb's constant (8.99 x 10^9 Nm^2/C^2), q1 and q2 are the charges, and r is the distance between them.

The force on 93 due to 92 is thus F_92-93 = k * |q_92 * q_93| / r_92-93^2 = 8.99 x 10^9 Nm^2/C^2 * 105 x 10^-6 C * 88 x 10^-6 C / (0.95 m)^2 = 741 N (direction towards 92 because the charges are of opposite signs).

Similarly, the force on 93 due to q1 can be calculated and added to the previous force to get the net force. Remember that q1 is not directly next to 93, but should consider the entire distance 0.50m + 0.95m for r_1-93.

Given that the content loaded Particles q1 = -53.0 mc is present scenario, and separated by 0.50 m with q2 and then it's further separated by 0.95 m from q3, the computation results in a net force on particle 93 that's dependent on these parameters.

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