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Answer :
Kiersten, with a z-score of 1.90, outperformed the others. She should be offered the job as she had the highest relative score on her version of the test.
To determine which applicant should be offered the job based on their aptitude test scores, we can use a statistical measure called z-scores. The z-score tells us how many standard deviations a particular score is from the mean. The higher the z-score, the better the applicant performed compared to others who took the test.
Here's how you can calculate the z-scores for each applicant:
1. For Rebecca:
Z-Rebecca = (Score-Rebecca - Mean-Rebecca) / Standard Deviation-Rebecca
Z-Rebecca = (97.8 - 72.3) / 15 = 1.72
2. For Frankie:
Z-Frankie = (Score-Frankie - Mean-Frankie) / Standard Deviation-Frankie
Z-Frankie = (272 - 242) / 20 = 1.50
3. For Kiersten:
Z-Kiersten = (Score-Kiersten - Mean-Kiersten) / Standard Deviation-Kiersten
Z-Kiersten = (7.66 - 6.9) / 0.4 = 1.90
Now, we have calculated the z-scores for each applicant. A higher z-score indicates a better performance relative to the mean of their respective test versions.
In this case, Kiersten has the highest z-score of 1.90, indicating that she performed the best relative to the other test takers in her version of the test. Therefore, based on the aptitude test scores, Kiersten should be offered the job.
To learn more about z-score here
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