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You sell a lot with a frontage of 59 feet and 8 inches on the street and a depth of 140 feet to the alley. Such sales in this area are based upon a charge per square foot. The lot you sold contained:

1. 872.7 sq ft
2. 1,293 sq ft
3. 8,353 sq ft
4. 8,472 sq ft

Answer :

Final answer:

The lot sold contained 8,353.8 square feet, which can be rounded to 8,353 square feet. Therefore, the correct answer is option 3. 8,353 sq ft.

Explanation:

To calculate the total square footage of a lot that has a frontage of 59 feet 8 inches and a depth of 140 feet, we first need to convert the inches to feet for unification of measurement. Since there are 12 inches in a foot, 8 inches is equal to ⅓ feet (≈ 0.67 feet). The frontage in feet will therefore be 59 + 0.67 = 59.67 feet.

Next, we multiply the frontage by the depth to get the area in square feet:
59.67 feet (frontage) × 140 feet (depth) = 8,353.8 square feet.

Therefore, the lot sold contained 8,353.8 square feet, which can be rounded to 8,353 square feet if we are using whole numbers for measurement. This corresponds with option 3 from the choices provided.

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