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Answer :
Final answer:
19200 Joules of heat energy is needed to raise the temperature of 10 kg of lead by 15 degrees Celsius.
Explanation:
The amount of heat energy required to change the temperature of a substance can be calculated using the formula Q = mcΔT, where:
- Q is the amount of heat energy,
- m is the mass of the substance,
- c is the specific heat capacity of the substance, and
- ΔT is the change in temperature.
Given that the mass (m) of lead is 10 kg, the specific heat capacity (c) is 128 J/kg K, and the change in temperature (ΔT) is 15 degrees Celsius, we can substitute these values into our formula to get:
Q = 10 kg * 128 J/kg K * 15 K
= 19200 J
Therefore, 19200 Joules of heat energy is required to raise the temperature of 10 kg of lead by 15 degrees Celsius.
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