Answer :

Final answer:

The 20kg boy would be raised 98 meters above the ground with 196x10^2 joules of energy using the gravitational potential energy formula, PE = mgh, where PE is the energy in joules, m is the mass in kilograms, g is the gravitational field strength (approximated to 10 m/s^2), and h is the height in meters.

Explanation:

To determine how high a 20kg boy can be raised with 196x10^2 J of energy, we use the formula for gravitational potential energy (PE), which is PE = mgh, where m is mass, g is the acceleration due to gravity (approximately 9.8 m/s2, but often rounded to 10 m/s2 for ease of calculation), and h is the height in meters.

First, convert the energy to joules. We have 196*102, which is 19600 J. Set up the equation using the known values:

19600 J = (20 kg)(10 m/s^2)h

To solve for h, divide both sides by (20 kg)(10 m/s^2):

h = 19600 J / (20 kg * 10 m/s^2)

h = 19600 J / 200 kg·m/s^2

h = 98 meters

Hence, the boy would be raised 98 meters above the ground using 19600 joules of energy.

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Rewritten by : Barada