Answer :

First, convert the volume from milliliters to liters. Since there are 1000 mL in 1 L, the volume in liters is given by

[tex]$$
\text{Volume in L} = \frac{7000 \text{ mL}}{1000} = 7 \text{ L}.
$$[/tex]

Next, use the definition of molarity: a 0.6 M solution contains 0.6 moles of solute per liter of solution. The number of moles ([tex]$n$[/tex]) of the solute is calculated as

[tex]$$
n = \text{molarity} \times \text{volume in L} = 0.6 \times 7.
$$[/tex]

Thus, the number of moles is

[tex]$$
n = 4.2 \text{ moles}.
$$[/tex]

So, there are [tex]$4.2$[/tex] moles of [tex]$\text{Ba(ClO}_4\text{)}_2$[/tex] in 7000 mL of a 0.6 M solution.

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