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A student has 80 g of magnesium (Mg). What mass of magnesium chloride (MgCl₂) will they produce?

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Answer :

Final answer:

To determine the mass of magnesium chloride (MgCl₂) produced, we first need to calculate the moles of magnesium (Mg) using its molar mass. Then, we use the balanced equation to calculate the moles of MgCl₂ produced. Finally, we can calculate the mass of MgCl₂ produced using its molar mass.

Explanation:

To determine the mass of magnesium chloride (MgCl₂) produced, we first need to calculate the moles of magnesium (Mg) using its molar mass. The molar mass of Mg is 24.305 g/mol. So, 80 g of Mg is equal to:

80 g Mg * (1 mol Mg / 24.305 g Mg) = 3.29 mol Mg

Since the balanced equation shows that 1 mol of Mg reacts with 2 mol of HCl to produce 1 mol of MgCl₂, the moles of MgCl₂ produced will be:

3.29 mol Mg * (1 mol MgCl₂ / 1 mol Mg) = 3.29 mol MgCl₂

Finally, we can calculate the mass of MgCl₂ produced using its molar mass:

3.29 mol MgCl₂ * (95.212 g MgCl₂ / 1 mol MgCl₂) = 312.98 g

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