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About 2% of the population has a particular genetic mutation.

198 people are randomly selected.

1. Find the mean for the number of people with the genetic mutation in such groups of 198.

2. Find the standard deviation for the number of people with the genetic mutation in such groups of 198.

(Round to the nearest 2 decimal places.)

Answer :

Final answer:

The mean number of people with the genetic mutation in groups of 198 is 3.96. The standard deviation for the number of people with the genetic mutation in groups of 198 is 3.07.

Explanation:

To find the mean for the number of people with the genetic mutation in groups of 198, we can use the formula:

Mean = (p)(n)

where p is the probability of having the genetic mutation (2% or 0.02) and n is the number of people in each group (198). Plugging in the values, we get:

Mean = (0.02)(198) = 3.96

To find the standard deviation for the number of people with the genetic mutation in groups of 198, we can use the formula:

Standard Deviation = √((p)(1-p)(n))

Using the same values as before, we can calculate:

Standard Deviation = √((0.02)(0.98)(198)) = 3.07

Learn more about mean and standard deviation here:

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