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Find [tex]f'(x)[/tex] for [tex]f(x) = 2x^3 - 4x^2 + 6x - 25[/tex].

A) [tex]6x^2 - 8x - 19[/tex]
B) [tex]6x^2 - 8x + 6[/tex]
C) [tex]x^3 - 4x^2 + 6[/tex]
D) [tex]4x - 25[/tex]

Answer :

To calculate f'(x) for the function f(x) = 2x^3 - 4x^2 + 6x - 25, apply the power rule to obtain f'(x) = 6x^2 - 8x + 6, so the correct answer is B) 6x^2 - 8x + 6.

To find the derivative f'(x) for the function f(x) = 2x3 - 4x2 + 6x - 25, we'll apply the power rule for derivatives. The power rule states that the derivative of xn is nxn-1.

Using the power rule on each term:

  • The derivative of 2x3 is 6x2.
  • The derivative of -4x2 is -8x.
  • The derivative of 6x is 6.
  • The derivative of any constant, such as -25, is 0.

Combining these results, the derivative f'(x) is:

f'(x) = 6x2 - 8x + 6

Therefore, the correct answer is B) 6x2 - 8x + 6.

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