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Answer :
Final answer:
The total mass of water in the beaker is the sum of the initial mass (108.2 g) and the mass of water added (38.4 g), resulting in a total of 146.6 g.
Explanation:
The student has poured 38.4 g of water into a beaker containing 108.2 g of water. Given that the density of water at 13°C is 1.00 g/mL, the total mass of water in the beaker is the sum of the two masses. Therefore, we calculate the total mass by adding the mass of water initially in the beaker to the mass of water added.
To find the total mass of water in the beaker:
- Mass of water initially in the beaker = 108.2 g
- Mass of water added = 38.4 g
- Total mass of water in the beaker = 108.2 g + 38.4 g = 146.6 g
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