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An elevator containing 3 passengers (with masses of 72 kg, 84 kg, and 35 kg) has a combined mass of 1030 kg. The cable attached to the elevator exerts an upward force of 9800 N. What is the acceleration and direction of the elevator at this instance?

Answer :

Final answer:

The acceleration of the elevator, moving in the upward direction, given the supplied forces and masses, is 8.02 m/s^2.

Explanation:

Firstly, calculate the total mass in the elevator by adding the masses of the 3 passengers and the mass of the elevator itself. That sums up to 72 kg + 84 kg + 35 kg + 1030 kg = 1221 kg. The force exerted by the elevator cable is 9800 N. According to Newton's second law of motion, force equals mass times acceleration (F=ma), so acceleration can be determined by rearranging this equation to a = F/m. Plugging the values in, we get a = 9800 N / 1221 kg = 8.02 m/s^2. This is the acceleration of the elevator, and since the force is upward, the elevator is moving upwards.

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