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How much heat is absorbed by a [tex]2.00 \times 10^3 \, \text{kg}[/tex] granite boulder as its temperature changes from [tex]10 \, ^\circ \text{C}[/tex] to [tex]29 \, ^\circ \text{C}[/tex]?

Answer :

Final answer:

The amount of heat absorbed by a 2.00 x 10³ granite boulder as its temperature changes from 10 ⁰C to 29 ⁰C can be calculated using the formula q=mcΔT, yielding a value of approximately 3.0 x 10⁸ J.

Explanation:

To calculate the amount of heat absorbed by a granite boulder as its temperature changes, we need to apply the formula q = mcΔT, where:

q is the heat absorbed,

m is the mass of the substance (in this case, the granite boulder),

c is the specific heat capacity of the substance, and

ΔT is the change in temperature.

The specific heat capacity of granite is approximately 0.790 J/g °C.

Therefore, for your question, where the mass of the boulder is 2.00 x 10³ kg (or 2.00 x 10⁶ g), the change in temperature (ΔT) is 29 ⁰C - 10 ⁰C = 19 ⁰C, we can substitute these values into the formula:

q = (2.00 x 10⁶ g) x (0.790 J/g °C) x (19 °C) = approximately 3.0 x 10⁸ J

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