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Mu Alpha Theta, a math honorary club, wants to raise money by selling cards and bouquets of flowers for Valentine's Day. The cards cost the club $2 each, and bouquets cost $3.50 each. Mu Alpha will sell the cards for $6 each and the flowers for $8 each. The club can spend $360 to buy the cards and flowers, and it aims to collect $900 from its sales.

Which linear equation represents this scenario?

A. 2x + 3.5y = 360; 6x - 8y = 900
B. 2x + 3.5y = 360; 8x + 6y = 900
C. 2x - 3.5y = 360; 6x + 8y = 900
D. 2x + 3.5y = 360; 6x + 8y = 900
E. 2x + 6y = 360; 3.5x + 8y = 900
F. No equation.

Answer :

Answer:

900

Step-by-step explanation:

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Rewritten by : Barada

2x+3.5y=360 and 6x+8y=900 are two linear equation that represents the given scenario.

We need to find the linear equations for the given situation.

What is the simultaneous equation?

Equations involving two or more unknowns that are to have the same values in each equation.

Let the number of cards be x and the number of flowers be y.

Cards cost the club $2 each; bouquets cost the club $3.50 each. The club can spend $360 to buy the cards and the flowers.

Now, 2x+3.5y=360

Mu Alpha will sell the cards for $6 each, and the flowers for $8 each. It wants to collect $900 from its sales.

Now, 6x+8y=900

Therefore, 2x+3.5y=360 and 6x+8y=900 are two linear equation that represents the given scenario.

To learn more about linear equations visit:

https://brainly.com/question/11897796.

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