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Answer :
Answer : The volume of the gas is, 101 liters
Solution :
Using ideal gas equation :
[tex]PV=nRT\\\\V=\frac{nRT}{P}[/tex]
where,
n = number of moles of gas = 35.8 moles
P = pressure of the gas = 10.0 atm
T = temperature of the gas = [tex]70^oC=273+70=343K[/tex]
R = gas constant = 0.0821 L.atm/mole.K
V = volume of gas = ?
Now put all the given values in the above equation, we get the volume of the gas.
[tex]V=\frac{nRT}{P}[/tex]
[tex]V=\frac{35.8mole\times (0.0821L.atm/mole.K)\times 343K}{10atm}[/tex]
[tex]V=100.81L\approx 101L[/tex]
Therefore, the volume of the gas is, 101 liters
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Rewritten by : Barada
PV = n RT
P: pressure =10atm
V volume
n number of mole = 35.8 moles
R universal gas constant = 0.082
T: The temperature= 70°C= 343.15 Kelvin
V= (n RT) / P = 35.8 x 0.082 x 343.15 / 10 = 100.7 ≈ 101 L
V = 101L
