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Answer :
Final answer:
To prepare a 1.5M sodium hydroxide (NaOH) solution in 145 mL, you would require approximately 8.7 grams of NaOH.
Explanation:
To find the number of grams of sodium hydroxide needed, we first need to understand the concept of molarity. 1 M represents 1 mol of solute in 1 liter of solution. As we know, 1 L =1000 mL, so if we want to prepare a 1.5 M solution in 145 mL, we first convert the volume to liters: 0.145 L. Hence, the moles of sodium hydroxide can be calculated as: moles = Molarity * Volume(L) = 1.5M * 0.145L = 0.2175 mol. The molecular weight of sodium hydroxide (NaOH) is approximately 40 g/mol, so the weight of sodium hydroxide required is: weight = moles * molecular weight = 0.2175 mol * 40 g/mol = 8.7g (rounded to the nearest decimal).
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