High School

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The density of gold is 19.3 g/cm\(^3\). A piece of gold displaces 2 mL of water. The specific gravity of gold is:

A. 19.3
B. 38.6
C. 9.6
D. 0.10

Answer :

Answer:

A) 19.3

Explanation:

As we know that specific gravity is defined as the ratio of weight of the object and weight of the water displaced by the object

so it is given by

[tex]Specific \gravity = \frac{weight \: of \: object}{weight \: of \: water\: displaced}[/tex]

now we have

weight of the object = (density)(volume)g

weight of object = [tex](19.3 g/cm^3)(2 mL)g[/tex]

now weight of the liquid displaced is given by

weight of water displaced = [tex](1 g/cm^3)(2 mL)g[/tex]

now we have

specific gravity = [tex]\frac{(19.3)(2mL)g}{(1)(2 mL)g}[/tex]

specific gravity = 19.3

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Rewritten by : Barada

The answer to this is 19.3