High School

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What volume of ethyl alcohol is contained in 35 mL (1 oz.) of 86 proof liquor, which is 43% (v/v) alcohol?

A. 30 mL
B. 37 mL
C. 15 mL
D. 43 mL

Answer :

The volume of ethyl alcohol in the liquor is approximately (C) 15 mL, calculated from 35 mL of 43% ABV liquor.

Here's how to find the volume of ethyl alcohol in the liquor:

Proof Conversion:

Proof is defined as twice the alcohol by volume (ABV) in the US.

We are given 86 proof liquor, so ABV = Proof / 2 = 86 / 2 = 43%

Calculate Alcohol Volume:

We have 35 mL of liquor (total volume).

The liquor is 43% alcohol by volume (ABV).

Alcohol volume = Total volume * ABV

Solve:

Alcohol volume = 35 mL * 43% = 15.05 mL (approximately)

Since the answer choices are whole numbers, we can round the calculated value (15.05 mL) to the nearest whole number. In this case, rounding down to the nearest whole number is appropriate because we're dealing with volume.

Therefore, the volume of ethyl alcohol in the liquor is C. 15 mL.

Complete question:

What volume of ethyl alcohol is contained in 35 mL (1 oz.) of 86 proof liquor, which is 43% (/v) alcohol?

A 30

B 37 mL

C 15 mL

D 43 mL

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Rewritten by : Barada

Answer:To find the volume of ethyl alcohol contained in 35 mL (1 oz.) of 86 proof liquor, which is 43% (v/v) alcohol, we can use the following steps:

Calculate the volume of pure alcohol in the liquor.

Convert the volume of pure alcohol to mL.

Step 1: Calculate the volume of pure alcohol:

Since the liquor is 43% alcohol by volume, we can calculate the volume of pure alcohol as follows:

Volume of pure alcohol

=

43

100

×

35

mL

Volume of pure alcohol=

100

43

×35 mL

Step 2: Convert the volume of pure alcohol to mL:

Since 1 oz. is approximately 29.5735 mL, and the volume of pure alcohol is given in terms of percent by volume, we have:

Volume of pure alcohol in mL

=

(

43

100

×

35

)

×

29.5735

1

Volume of pure alcohol in mL=(

100

43

×35)×

1

29.5735

Now, let's calculate:

Volume of pure alcohol in mL

=

(

43

100

×

35

)

×

29.5735

1

Volume of pure alcohol in mL=(

100

43

×35)×

1

29.5735

=

(

43

100

×

35

)

×

29.5735

=(

100

43

×35)×29.5735

=

(

15.05

)

×

29.5735

=(15.05)×29.5735

445.96

mL

≈445.96 mL

Therefore, the volume of ethyl alcohol contained in 35 mL (1 oz.) of 86 proof liquor is approximately 446 mL.

None of the given options match this result, but closest would be D43 mL.

Explanation: