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A string attached to an engine pulls a box 220 m along a horizontal road. The string makes an angle of 36° with the horizontal, and the tension in the string is 320 N. Find the work done by the engine.

A. 28.5 kJ
B. 37.6 kJ
C. 114 kJ
D. 57.0 kJ
E. 85.4 kJ

Answer :

Final answer:

The work done by the engine in this case is calculated using the formula: Work Done = Force x Displacement x cos(θ), which when the provided values are inputed results in an answer of approximately 57.0 kJ. Therefore, the correct answer is D: 57.0 kJ

Explanation:

This question is about the concept of work done in Physics. Work done by a force is calculated as the product of the force (in this case, tension in the string) and the displacement over which the force is applied, provided the force and displacement are in the same direction.

In this case, the force, or tension, is not directly aligned with the displacement; the string makes an angle (θ) of 36 degrees with the horizontal. So, only the component of the force that is in the direction of displacement contributes to the work done. Therefore, the workdone can be calculated using the formula: Workdone = Force × Displacement × cos(θ). Here, Force = 320 N, Displacement = 220 m, and θ = 36 degrees.

Applying these values into formula, we find the work done to be approximately 57.0 kJ. So, the correct answer is D: 57.0 kJ.

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