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A toy rocket is launched straight up into the air with initial velocity of 60 ft/s from a table 3ft above the ground. If acceleration due to gravity is the -16ft , approximately how many seconds after the launch will the toy rocket reach the ground

A toy rocket is launched straight up into the air with initial velocity of 60 ft s from a table 3ft above the ground If

Answer :

Final answer:

The toy rocket will reach the ground approximately 2.04 seconds after the launch.

Explanation:

To find the time it takes for the toy rocket to reach the ground, we can use the equation of motion: distance = initial velocity * time + (1/2) * acceleration * time^2. Since the toy rocket is launched straight up, the initial velocity is positive 60 ft/s, the distance is negative 3 ft (because it is above the ground), and the acceleration is negative 16 ft/s^2. We can plug these values into the equation and solve for time:

Distance = (-3) = (60 * t) + (1/2) * (-16) * t^2

After simplifying the equation, we get the quadratic equation 8t^2 - 60t - 3 = 0. By solving this equation, we find that the toy rocket will reach the ground approximately 2.04 seconds after the launch.

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