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6- Consider the following data related to the hardness of product. Find control limits for M observations, and find which of the samples are out of control. Sample Hardness of the product 36.3 28.6 32

Answer :

The product standard deviation control limits for the M observations are approximately 20.76 (LCL) and 44.51 (UCL).The none of the samples are out of control based on the given data.

To find the control limits for M observations and identify any samples that are out of control, to calculate the mean (x) and standard deviation (S) of the given data. The control limits are typically set at ±3 standard deviations from the mean.

Given the data: 36.3, 28.6, 32

Calculate the mean (x):

x = (36.3 + 28.6 + 32) / 3 = 97.9 / 3 = 32.6333

Calculate the standard deviation (S):

S = √((∑(Xi - x)²) / (n - 1))

= √(( (36.3 - 32.6333)² + (28.6 - 32.6333)² + (32 - 32.6333)² ) / (3 - 1))

= √((14.684 + 16.304 + 0.4056) / 2)

= √(31.3936 / 2)

= √(15.6968)

≈ 3.959

Calculate the control limits:

Upper Control Limit (UCL) = x + 3S

= 32.6333 + (3 ×3.959)

≈ 32.6333 + 11.877

≈ 44.51

Lower Control Limit (LCL) = x - 3S

= 32.6333 - (3 × 3.959)

≈ 32.6333 - 11.877

≈ 20.76

Identify samples that are out of control:

To determine if a sample is out of control, we compare the hardness measurements to the control limits.

The given data points are: 36.3, 28.6, 32.

Checking each data point:

36.3 is within the control limits (20.76 to 44.51).

28.6 is within the control limits (20.76 to 44.51).

32 is within the control limits (20.76 to 44.51).

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