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Determine the concentration of a solution made by dissolving 27.8 g of sodium chloride in 750.0 mL of solution.

A) 0.634 M
B) 0.566 M
C) 37.1 M
D) 0.475 M

Answer :

To determine the concentration (molarity) of the sodium chloride solution, we follow these steps:

1. Calculate the number of moles of sodium chloride using the formula:
[tex]$$
n = \frac{m}{M}
$$[/tex]
where
- [tex]$m = 27.8\, \text{g}$[/tex] is the mass of sodium chloride,
- [tex]$M = 58.44\, \text{g/mol}$[/tex] is the molar mass of sodium chloride.

Thus,
[tex]$$
n = \frac{27.8}{58.44} \approx 0.4757\, \text{mol}
$$[/tex]

2. Convert the volume of the solution from milliliters to liters:
[tex]$$
750.0\, \text{mL} = 0.7500\, \text{L}
$$[/tex]

3. Calculate the molarity of the solution using:
[tex]$$
C = \frac{n}{V}
$$[/tex]
where
- [tex]$n \approx 0.4757\, \text{mol}$[/tex] is the number of moles, and
- [tex]$V = 0.7500\, \text{L}$[/tex] is the volume in liters.

Therefore,
[tex]$$
C = \frac{0.4757}{0.7500} \approx 0.6343\, \text{M}
$$[/tex]

Since the answer options include 0.634 M, the concentration of the solution is

[tex]$$\boxed{0.634\, \text{M}}.$$[/tex]

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