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Write the balanced formula equation for the acid-base reaction that occurs when aqueous strontium hydroxide and hydroiodic acid are mixed.

A. Sr(OH)₂(aq) + 2HI(aq) → SrI₂(aq) + 2H₂O(l)

B. Sr(OH)₂(aq) + 2HI(aq) → SrI₂(aq) + 2H₂(g)

C. Sr(OH)₂(aq) + HI(aq) → SrI₂(aq) + H₂O(l)

D. Sr(OH)₂(aq) + HI(aq) → SrI₂(s) + 2H₂O(l)

Answer :

Final answer:

The balanced chemical equation for the reaction between strontium hydroxide and hydroiodic acid is Sr(OH)2(aq) + 2HI(aq) → SrI2(aq) + 2H2O(l). It's a neutralization reaction resulting in strontium iodide and water.

Explanation:

The balanced formula equation for the acid-base reaction occurring when aqueous strontium hydroxide and hydroiodic acid are mixed is:

Sr(OH)2(aq) + 2HI(aq) → SrI2(aq) + 2H2O(l)

Here, we have strontium hydroxide, a strong base, reacting with hydroiodic acid, a strong acid. When they react, they form strontium iodide and water, which is a typical neutralization reaction.

To ensure the equation is balanced, identify and match the number of each type of atom on both sides of the reaction. For example, there are two hydrogen ions (H+) from Hydroiodic acid, which combine with the two hydroxide ions (OH−) from Strontium hydroxide to form two water molecules (H2O).

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