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If a 1500 kg flywheel is spinning at 128 rad/s, what is its rotational kinetic energy?

A. 1,228,800 J
B. 2,457,600 J
C. 3,686,400 J
D. 4,915,200 J

Answer :

Final answer:

The rotational kinetic energy of a flywheel can be calculated using the formula K = 0.5 * I * π², where I is the moment of inertia and π is the angular velocity. In this case, the moment of inertia can be calculated as I = 0.5 * m * r², where m is the mass and r is the radius. Plugging in the given values, the rotational kinetic energy is 1,228,800 J.

Explanation:

The rotational kinetic energy of a flywheel can be calculated using the formula:

K = 0.5 * I * π²

Where K is the rotational kinetic energy, I is the moment of inertia, and π is the angular velocity.

In this case, the moment of inertia can be calculated as I = 0.5 * m * r², where m is the mass and r is the radius.

So, the rotational kinetic energy is:

K = 0.5 * (0.5 * 1500 kg * r²) * (128 rad/s)²

Using the given values, we can calculate the kinetic energy as:

K = 0.5 * (0.5 * 1500 kg * r²) * (128 rad/s)² = 1,228,800 J

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