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Question: You are performing a test cross of wolves. You know the following about the genetic traits:

- Friendliness is a recessive trait: [tex]f = \text{friendly}[/tex], [tex]F = \text{fierce}[/tex]
- Coat color is a dominant trait: [tex]B = \text{black}[/tex], [tex]b = \text{brown}[/tex]

You have a black and friendly wolf and a black and fierce wolf. You mate the two.

Given that 1 out of 8 pups are brown and friendly, if there are 16 pups, determine how many pups have each genotype and phenotype.

In other words, what are the genotypic and phenotypic ratios?

Answer :

Among 16 wolf pups being test-crossed, given the given traits and ratios, 2 pups are projected to be brown and friendly (recessive traits), and the remaining 14 are projected to be black and fierce (dominant traits).

The subject matter of this question is genotype and phenotype in genetic crossing, specifically applied to wolves' traits.

Given that 1 out of 8 pups are brown and friendly, we can assume that these traits—being friendly (which we know is recessive) and having a brown coat (which takes place when the black coat - a dominant trait - is missing) happen together.

So, given the number of total pups, which is 16, we can simply follow the given ratio to find the number of pups with each genotype and phenotype.

That is, 2 pups are brown and friendly (bf), and the remaining 14 pups are black and fierce (BF).

This is because in a test-cross, the dominant phenotype in the offspring (black and fierce) suggests the unknown genotype in the parent is likely homozygous dominant (BBFF).

To know more about genotype visit:

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