High School

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The equation is given by [tex]Q = 650 \left( \frac{1}{2} \right) \left( \frac{1}{13.1} \right)[/tex].

Answer parts (a) through (d).

(a) Determine the time it takes for the level of iodine-123 to drop to [tex]50 \, \mu \text{Ci}[/tex].

A. 13.1 hr
B. 26.2 hr
C. 39.3 hr
D. 52.4 hr

Answer :

Final answer:

The equation given represents the decay of iodine-123. By solving for the time it takes for the level of iodine-123 to drop to 50μCi, is 39.3 hours. so,the correct option is:(c) 39.3 hr

Explanation:

The equation $Q = 650(\frac{1}{2})(\frac{1}{13.1})$ represents the decay of iodine-123. To determine the time it takes for the level of iodine-123 to drop to 50μCi, we need to calculate the value for Q when it equals 50. By setting up and solving the equation, we can find the time, which is 39.3 hours.

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