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Answer :
The number of grams of [tex]Fe_{2} O_{3}[/tex] in 1.00 mole of Fe2O3 is 159.7 g which was calculated from the given values.
To determine the number of grams of [tex]Fe_{2} O_{3}[/tex] in 1.00 mole of Fe2O3, we need to know the molar mass of [tex]Fe_{2} O_{3}[/tex].
The molar mass of [tex]Fe_{2} O_{3}[/tex] can be calculated by adding up the atomic masses of its constituent elements, iron (Fe) and oxygen (O):
Fe: atomic mass = 55.85 g/mol
O: atomic mass = 16.00 g/mol
The molar mass of [tex]Fe_{2} O_{3}[/tex] = (2 x Fe atomic mass) + (3 x O atomic mass)
= (2 x 55.85 g/mol) + (3 x 16.00 g/mol)
= 111.7 g/mol + 48.00 g/mol
= 159.7 g/mol
Therefore, 1.00 mole of Fe2O3 weighs 159.7 grams.
The number of grams of Fe2O3 in 1.00 mole of Fe2O3 is 159.7 g.
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