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Answer :
Final answer:
Of the three isobars given (Cadmium-114, Indium-114, and Tin-114), Tin-114 is likely to be radioactive. It undergoes beta decay, transforming into Indium-114 while releasing an electron and an anti-neutrino.
Explanation:
The isotopes mentioned in the question are isobars, meaning they have the same mass number but different atomic numbers. They are 48 114 Cd (Cadmium-114), 49 114 In (Indium-114), and 50 114 Sn (Tin-114). Isobars can behave differently in terms of their stability: some can be radioactive while others are not.
The cadmium isotope (48 114 Cd) is known to be stable. For the indium isotope (49 114 In), there is not enough information, but it's also typically stable. However, the tin isotope, 50 114 Sn (Tin-114), is known to be radioactive. It undergoes beta decay and transforms into 49 114 In (Indium-114), releasing an electron and an anti-neutrino in the process.
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