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A steel rod near a blacksmith furnace is 1.00 m long, with a mass of 1.7 kg and cross-sectional area of 1.00 x 10-4. If the rod absorbs 4.0 x 103 J. Find the increase in length of the rod.​

A steel rod near a blacksmith furnace is 1 00 m long with a mass of 1 7 kg and cross sectional area of 1

Answer :

Final answer:

The increase in length of the steel rod is 2.0 x 10^-4 meters

Explanation:

To find the increase in length of the steel rod, we can use the formula:

ΔL = (F * L * ΔT) / (A * Y)

Where:

  • ΔL is the change in length
  • F is the force applied (obtained from the energy absorbed)
  • L is the original length of the rod
  • ΔT is the change in temperature
  • A is the cross-sectional area of the rod
  • Y is the Young's modulus of steel

Plugging in the values, we have:

ΔL = (4.0 x 10^3 J * 1.00 m) / (1.00 x 10^-4 m² * 200 x 10^9 N/m²)

ΔL = 2.0 x 10^-4 m

The increase in length of the rod is 2.0 x 10^-4 meters.

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